David Gross, H. Politzer, Frank Wilczek, Nobel Prize winners for physics in 2004

\(

\def\cuberoot#1{\sqrt[3]{#1}} \def\fourthroot#1{\sqrt[4]{#1}}

\def\abspartial#1#2#3#4{\left|\,{\partial(#1,#2)\over\partial(#3,#4)}\,\right|} \def\absdeltal#1#2#3#4{\left|\,{\d(#1,#2)\over\d(#3,#4)}\,\right|} \def\dispop#1#2{\disfrac{\partial #1}{\partial #2}}

\def\definedas{\equiv}

\def\bb{{\bf b}} \def\bB{{\bf B}} \def\bsigma{\boldsymbol{\sigma}} \def\bx{{\bf x}} \def\bu{{\bf u}}

\def\Re{{\rm Re\hskip1pt}} \def\Reals{{\mathbb R\hskip1pt}} \def\Integers{{\mathbb Z\hskip1pt}} \def\Naturals{{\mathbb N\hskip1pt}} \def\Im{{\rm Im\hskip1pt}} \def\P{\mbox{P}}

\def\half{{\textstyle{1\over 2}}} \def\third{{\textstyle{1\over3}}} \def\fourth{{\textstyle{1\over 4}}} \def\fifth{{\scriptstyle{1\over 5}}} \def\sixth{{\textstyle{1\over 6}}}

\def\oA{\rlap{$A$}\kern2pt\overline{\phantom{\dis{}I}}\kern.5pt} \def\obA{\rlap{$A$}\kern2pt\overline{\phantom{\dis{}I}}\kern.5pt} \def\obX{\rlap{$X$}\kern2pt\overline{\phantom{\dis{}I}}\kern.5pt} \def\obY{\rlap{$Y$}\kern2pt\overline{\phantom{\dis{}I}}\kern.5pt} \def\obZ{\rlap{$Z$}\kern2pt\overline{\phantom{\dis{}I}}\kern.5pt}

\def\obc{\rlap{$c$}\kern2pt\overline{\phantom{\dis{}I}}\kern.5pt} \def\obd{\rlap{$d$}\kern2pt\overline{\phantom{\dis{}I}}\kern.5pt} \def\obk{\rlap{$k$}\kern2pt\overline{\phantom{\dis{}I}}\kern.5pt} \def\oba{\rlap{$a$}\kern2pt\overline{\phantom{\dis{}I}}\kern.5pt} \def\obb{\rlap{$b$}\kern1pt\overline{\phantom{\dis{}t}}\kern.5pt}

\def\obw{\rlap{$w$}\kern1pt\overline{\phantom{\dis{}t}}\kern.5pt}

\def\obz{\overline{z}}\kern.5pt}

\newcommand{\bx}{\boldsymbol{x}} \newcommand{\by}{\boldsymbol{y}}

\newcommand{\br}{\boldsymbol{r}} \renewcommand{\bk}{\boldsymbol{k}}

\def\cuberoot#1{\sqrt[3]{#1}} \def\fourthroot#1{\sqrt[4]{#1}} \def\fifthroot#1{\sqrt[5]{#1}} \def\eighthroot#1{\sqrt[8]{#1}} \def\twelfthroot#1{\sqrt[12]{#1}}

\def\dis{\displaystyle} %\def\definedas{\equiv}

\def\bq{{\bf q}} \def\bp{{\bf p}}

\def\abs#1{\left|\,#1\,\right|} \def\disfrac#1#2{{\displaystyle #1\over\displaystyle #2}}

\def\select#1{ \langle\, #1 \,\rangle } \def\autoselect#1{ \left\langle\, #1 \,\right\rangle }

\def\bigselect#1{ \big\langle\, #1 \,\big\rangle }

\renewcommand{\ba}{\boldsymbol{a}} \renewcommand{\bb}{\boldsymbol{b}} \newcommand{\bc}{\boldsymbol{c}} \newcommand{\bh}{\boldsymbol{h}} \newcommand{\bA}{\boldsymbol{A}} \newcommand{\bB}{\boldsymbol{B}} \newcommand{\bC}{\boldsymbol{C}} \newcommand{\definedas}{\equiv} \newcommand{\half}{\frac{1}{2}}

%\newcommand{\slfrac}[2]{\raisebox{0.5pt}{$\scriptstyle{}^{#1}\!/\!_{#2}$}} \def\slfrac#1#2{\raise.8ex\hbox{$\scriptstyle#1$}\!/\!\lower.5ex\hbox{$\scriptstyle#2$}}

\newcommand{\bsigma}{\boldsymbol \sigma} \newcommand{\abs}[1]{\left|\,#1\,\right|} \newcommand{\Rectangle}{\sqsubset\!\sqsupset}

\newcommand{\rectangle}{{% \ooalign{$\sqsubset\mkern3mu$\cr$\mkern3mu\sqsupset$\cr}%

% How to do fractions: for 1/2 use this in place: $\raise{0.8pt}{\scriptstyle{}^{1}\!/\!_{2}}$ % for n/m use this in place: $\raise{0.8pt}{\scriptstyle{}^{n}\!/\!_{m}}$

}}

\)

David Gross, H. Politzer, Frank Wilczek, Nobel Prize winners for physics in 2004

Patrick Reany

19 May 2026

Note: This chat I had with Copilot is likely edited for relevance and brevity. I often do not take the time to highlight all the words that Copilot highlights. Further, in the interest of being didactic, I might arbitrarily highlight an occasional word or phrase that Copilot did not. (Naturally, I get to correct my spelling, grammar, and other minor errors for free.)

I report as faithfully as I can what LLMs tell me, but I can't guarantee that they are correct on every factual matter. If the subject should touch on physical or mental self-care, regard the content merely for information sake, rather than medical advice.



Patrick:
Can you tell me a bit about David Gross, H. Politzer, and Frank Wilczek, the Nobel Prize winners for physics in 2004?

Copilot:
David Gross, H. David Politzer, and Frank Wilczek shared the 2004 Nobel Prize in Physics for one of the most important breakthroughs in modern particle physics: the discovery of asymptotic freedom in the theory of the strong interaction. [NobelPrize.org](https://www.nobelprize.org/prizes/physics/2004/summary/)


🧲 What they discovered: Asymptotic Freedom

Their work—published in 1973—showed that quarks interact more weakly the closer they are to each other, behaving almost like free particles at extremely short distances or high energies. Conversely, as quarks move apart, the strong force grows stronger, preventing quarks from ever being isolated. This explained why quarks are permanently confined inside protons and neutrons. [American Physical Society](https://www.aps.org/apsnews/2004/12/three-american-physicists-share-2004-nobel-physics-prize-for-qcd)

This counterintuitive behavior arises because the force carriers of the strong interaction—gluons—interact with each other as well as with quarks, unlike photons in electromagnetism. That self-interaction is what makes the strong force grow with distance.


🔬 Why this mattered

Their discovery provided the mathematical foundation for Quantum Chromodynamics (QCD), the modern theory of the strong nuclear force and a central pillar of the Standard Model. QCD explains:

Asymptotic freedom allowed physicists to perform precise calculations of quark–gluon interactions and match them with experimental results from particle accelerators. [American Physical Society](https://www.aps.org/apsnews/2004/12/three-american-physicists-share-2004-nobel-physics-prize-for-qcd)


👤 The laureates

Each received one‑third of the prize. [NobelPrize.org](https://www.nobelprize.org/prizes/physics/2004/summary/)


If you'd like, I can also place their work in the broader context of the Standard Model, compare it to other Nobel-winning discoveries in particle physics, or explain asymptotic freedom using math.

Patrick:
Yes, I'd like to see the asymptotic freedom using math.

Copilot:
Here’s the clean, mathematical heart of asymptotic freedom, written at the level you enjoy: structurally precise, conceptually transparent, and with the RG mechanics laid bare.


1. The β‑function is the whole story

Asymptotic freedom is the statement that the running coupling \( g(\mu) \) of a non‑Abelian gauge theory decreases as the energy scale \( \mu \) increases.

The renormalization group equation is

\[ \mu \frac{dg}{d\mu} = \beta(g). \]

To one loop, for an \(SU(N)\) gauge theory with \(n_f\) Dirac fermions in the fundamental representation,

\[ \beta(g) = -\,\frac{g^3}{16\pi^2}\left(\frac{11}{3}N - \frac{2}{3}n_f\right). \]

Define

\[ b_0 = \frac{1}{16\pi^2}\left(\frac{11}{3}N - \frac{2}{3}n_f\right). \]

Then

\[ \beta(g) = - b_0 g^3. \]

The sign of \(b_0\) determines everything.

For QCD: \(N=3\), \(n_f \le 16\), so \(b_0>0\).


2. Solve the RG equation explicitly

Start with

\[ \mu \frac{dg}{d\mu} = -b_0 g^3. \]

Separate variables:

\[ \frac{dg}{g^3} = -b_0 \frac{d\mu}{\mu}. \]

Integrate:

\[ -\frac{1}{2g^2(\mu)} = -b_0 \ln \mu + C. \]

Rewrite the integration constant in terms of a scale \(\Lambda\):

\[ \frac{1}{g^2(\mu)} = 2 b_0 \ln\!\left(\frac{\mu}{\Lambda}\right). \]

Thus the running coupling is

\[ g^2(\mu) = \frac{1}{2 b_0 \ln(\mu/\Lambda)}. \]

Or in the more standard QCD notation:

\[ \alpha_s(\mu) = \frac{g^2(\mu)}{4\pi} = \frac{1}{4\pi\,2 b_0 \ln(\mu/\Lambda_{\text{QCD}})}. \]

This is the famous logarithmic weakening of the strong force.


3. The physical meaning is encoded in the denominator

As \(\mu \to \infty\):

\[ \ln(\mu/\Lambda) \to \infty \quad\Rightarrow\quad g(\mu) \to 0. \]

As \(\mu \to \Lambda\):

\[ \ln(\mu/\Lambda) \to 0^+ \quad\Rightarrow\quad g(\mu) \to \infty. \]

This is the mathematical expression of:

The same formula encodes both behaviors.


4. Why non‑Abelian gauge theories have the right sign

The one‑loop coefficient decomposes into two contributions:

\[ b_0 = \frac{1}{16\pi^2} \left[ \underbrace{\frac{11}{3}N}_{\text{gluons}} - \underbrace{\frac{2}{3}n_f}_{\text{quarks}} \right]. \]

Asymptotic freedom requires the gluon term to dominate:

\[ \frac{11}{3}N > \frac{2}{3}n_f. \]

For QCD (\(N=3\)), this means \(n_f < 16.5\), which is true in nature.

This is the deep reason Gross, Politzer, and Wilczek won the Nobel Prize: non‑Abelian gauge fields anti‑screen their own charge.


5. The distance‑space interpretation

Using \(\mu \sim 1/r\), the running coupling becomes

\[ g^2(r) \sim \frac{1}{\ln(1/(r\Lambda))}. \]

As \(r \to 0\):

\[ g(r) \to 0 \quad\text{(quarks behave free)}. \]

As \(r \to \Lambda^{-1}\):

\[ g(r) \to \infty \quad\text{(confinement)}. \]

This is the mathematical backbone of the “quark freedom at short distances” picture.


6. If you want the two‑loop refinement

The two‑loop β‑function is

\[ \beta(g) = -b_0 g^3 - b_1 g^5, \]

with

\[ b_1 = \frac{1}{(16\pi^2)^2} \left(\frac{34}{3}N^2 - \frac{10}{3}N n_f - 2 C_F n_f\right), \quad C_F = \frac{N^2-1}{2N}. \]

The solution becomes

\[ \alpha_s(\mu) = \frac{1}{4\pi b_0 \ln(\mu^2/\Lambda^2)} \left[ 1 - \frac{b_1}{b_0^2} \frac{\ln\ln(\mu^2/\Lambda^2)}{\ln(\mu^2/\Lambda^2)} \right]. \]

This is the expression used in precision QCD.


If you want, we can go further:

Just tell me which direction you want to explore.

Patrick:
How about we go with options 3) and 4), please? The Wilsonian RG and the geometry of the coupling manifold and express the running coupling in Lambert‑W form.

Copilot:

Short answer — Wilsonian RG views asymptotic freedom as the flow of effective couplings when short‑distance modes are successively integrated out; the geometry of the coupling manifold is the space of couplings with a vector field given by the β‑function whose fixed points and stable/unstable directions control physics at long distances; the two‑loop RG can be inverted in closed form using the Lambert W function to give an explicit running coupling. [Physical Review Link Manager](https://link.aps.org/doi/10.1103/PhysRevB.4.3174) [NIST Digital Library of Mathematical Functions](https://dlmf.nist.gov/4.13)

Wilsonian Renormalization Group Overview

Key idea: integrate out momentum shells \(k\in[\Lambda/b,\Lambda]\) to produce an effective action for modes \(k<\Lambda/b\); rescale to restore the cutoff and read off how couplings change. The RG becomes a flow on the infinite‑dimensional space of actions; truncating to a finite set of couplings yields ordinary differential equations \(\mu\,d g_i/d\mu=\beta_i(g)\). This picture explains universality and why short‑distance details often only set a few relevant couplings. [Physical Review Link Manager](https://link.aps.org/doi/10.1103/PhysRevB.4.3174) [harvest.aps.org](https://harvest.aps.org/v2/journals/articles/10.1103/RevModPhys.55.583/fulltext)

Geometry of the Coupling Manifold

Two‑Loop RG and Lambert W Inversion

Start from the two‑loop β for the squared coupling (schematic form)

\[ \mu\frac{dg}{d\mu}=-b_0 g^3-b_1 g^5. \]

Change variable \(u=1/g^2\) to obtain an equation of the form

\[ \frac{du}{d\ln\mu}=2b_0+\frac{2b_1}{u}+\cdots, \]

which integrates to an implicit relation

\[ u + \frac{b_1}{b_0}\ln u = 2b_0\ln\!\frac{\mu}{\Lambda}. \]

This transcendental equation for \(u\) is inverted using the Lambert W function (solution of \(W e^{W}=z\)), giving an explicit closed form for the running coupling. One convenient form is

\[ g^2(\mu) = -\frac{1}{b_1}\frac{1}{1+W\!\Big(-\frac{1}{b_1}\Big(\frac{\mu}{\Lambda}\Big)^{-2b_0/b_1}\Big)}. \]

This expression reproduces the standard two‑loop asymptotic expansion at large \(\mu\) and is numerically useful because \(W\) handles the transcendental inversion exactly. Lambert W is the natural special function for inverting RG relations that mix algebraic and logarithmic dependence. [NIST Digital Library of Mathematical Functions](https://dlmf.nist.gov/4.13) [Chimera](https://chimera.roma1.infn.it/ENZO/FC/PAPERS/202311_nature_wilson_rg.pdf)

Practical Takeaways

If you want, I can derive the implicit two‑loop relation step by step and show the algebraic steps that produce the Lambert W inversion.

Patrick:
Yes, I'm interested to see this two-loop relation with algebraic steps.

Copilot:
Short answer: Starting from the two‑loop β‑function \(\beta(g)=-b_0 g^3-b_1 g^5\), change variables to \(u=1/g^2\), integrate to obtain the implicit relation \(\;u+\dfrac{b_1}{b_0}\ln u=2b_0\ln(\mu/\Lambda)\;\), and invert that transcendental equation exactly with the Lambert‑W function to get an explicit closed form for \(g^2(\mu)\). [arXiv.org](https://arxiv.org/abs/0706.1793) [Wikipedia](https://en.wikipedia.org/wiki/Beta_function_%28physics%29)

1. Start point: two‑loop β function

The two‑loop renormalization group equation (schematic, MS‑like scheme) is \[ \mu\frac{dg}{d\mu}=\beta(g)=-b_0 g^3-b_1 g^5, \] with \(b_0>0\) for asymptotic freedom in non‑Abelian gauge theories. [Wikipedia](https://en.wikipedia.org/wiki/Beta_function_%28physics%29) [arXiv.org](https://arxiv.org/abs/0706.1793)

2. Change of variable \(u=1/g^2\)

Define \[ u(\mu)\equiv \frac{1}{g^2(\mu)}. \] Differentiate with respect to \(\ln\mu\): \[ \frac{du}{d\ln\mu}=\frac{d}{d\ln\mu}\big(g^{-2}\big)=-2g^{-3}\frac{dg}{d\ln\mu}. \] Using \(\dfrac{dg}{d\ln\mu}=\beta(g)\) gives \[ \frac{du}{d\ln\mu}=-2g^{-3}(-b_0 g^3-b_1 g^5)=2b_0+2b_1 g^2. \] Replace \(g^2=1/u\) to obtain the rational form \[ \boxed{\;\frac{du}{d\ln\mu}=2b_0+\frac{2b_1}{u}\; }. \]

3. Integrate to the implicit relation

Separate variables and integrate with respect to \(\ln\mu\): \[ \int \Big(1-\frac{b_1}{b_0}\frac{1}{u}\Big)\,du = 2b_0\int d\ln\mu. \] A cleaner direct integration of \(\dfrac{du}{d\ln\mu}=2b_0+\dfrac{2b_1}{u}\) yields \[ u + \frac{b_1}{b_0}\ln u = 2b_0\ln\!\frac{\mu}{\Lambda}, \] where \(\Lambda\) is the integration constant (the RG invariant scale). This is the standard implicit two‑loop relation. [arXiv.org](https://arxiv.org/abs/0706.1793)

4. Put the equation in Lambert‑W form

Rearrange the implicit equation to isolate a factor of the form \(W e^{W}\). Let \[ u = -\frac{b_1}{b_0}\,W(z), \] and derive the argument \(z\) as follows. Exponentiate the implicit relation after moving \(u\) terms: \[ \exp\!\Big(\frac{b_0}{b_1}u\Big)\,u = \exp\!\Big(2\frac{b_0^2}{b_1}\ln\frac{\mu}{\Lambda}\Big). \] Multiply both sides by \(\dfrac{b_0}{b_1}\) and define \[ W\;=\;\frac{b_0}{b_1}u,\qquad z\;=\;\frac{b_0}{b_1}\Big(\frac{\mu}{\Lambda}\Big)^{2b_0^2/b_1}. \] Then \(W e^{W}=z\), so \(W=\!W_k(z)\) (Lambert W, branch \(k\)). Solving back for \(g^2=1/u\) gives a compact closed form.

5. Final explicit expression (one convenient form)

One convenient algebraic form is \[ \boxed{\; g^2(\mu)= -\frac{1}{b_1}\,\frac{1}{1+W_k\!\Big(-\frac{1}{b_1}\Big(\frac{\mu}{\Lambda}\Big)^{-2b_0/b_1}\Big)} \;}, \] where the branch \(k\) is chosen so that \(g^2>0\) for the physical \(\mu\) (for large \(\mu\) the principal branch \(k=0\) is used). Expanding this for large \(\mu\) reproduces the usual two‑loop asymptotic expansion. [arXiv.org](https://arxiv.org/abs/0706.1793)

6. Remarks and practical points

If you want, I can derive the exact algebraic steps that map the implicit \(u+\frac{b_1}{b_0}\ln u\) equation into the precise \(W e^{W}=z\) form (showing each substitution and constant), and then plot or evaluate \(g(\mu)\) numerically for QCD coefficients. [arXiv.org](https://arxiv.org/abs/0706.1793) [Wikipedia](https://en.wikipedia.org/wiki/Beta_function_%28physics%29)

Patrick:
Yes, please proceed.

Copilot:
In short: Starting from \(\beta(g)=-b_0 g^3-b_1 g^5\) and setting \(u\!=\!1/g^2\) one obtains the implicit two‑loop relation \(u+\dfrac{b_1}{b_0}\ln u=2b_0\ln(\mu/\Lambda)\); this transcendental equation is inverted exactly with the Lambert‑W function to give a closed form for \(g^2(\mu)\). [web2.ph.utexas.edu](https://web2.ph.utexas.edu/~vadim/Classes/2019f/qcd-beta.pdf) [NIST Digital Library of Mathematical Functions](https://dlmf.nist.gov/4.13)


Derivation: change of variables and integration

Start with the two‑loop RG equation \[ \mu\frac{dg}{d\mu}=\beta(g)=-b_0 g^3-b_1 g^5, \] with \(b_0>0\) for asymptotic freedom. Define \[ u(\mu)\equiv\frac{1}{g^2(\mu)}. \] Differentiate with respect to \(\ln\mu\): \[ \frac{du}{d\ln\mu}=-2g^{-3}\frac{dg}{d\ln\mu} = -2g^{-3}\beta(g) =2b_0+2b_1 g^2. \] Replace \(g^2=1/u\) to obtain the rational ODE \[ \boxed{\;\frac{du}{d\ln\mu}=2b_0+\frac{2b_1}{u}\; }. \] Integrate both sides (introducing the RG invariant scale \(\Lambda\)) to get the standard implicit two‑loop relation \[ \boxed{\;u+\frac{b_1}{b_0}\ln u = 2b_0\ln\!\frac{\mu}{\Lambda}\; }. \] This step and the change \(u=1/g^2\) are standard in QCD RG manipulations. [web2.ph.utexas.edu](https://web2.ph.utexas.edu/~vadim/Classes/2019f/qcd-beta.pdf) [Wikipedia](https://en.wikipedia.org/wiki/Beta_function_%28physics%29)


Put the equation into Lambert‑W form

We want to solve for \(u\) from \[ u + a\ln u = X, \qquad a\equiv\frac{b_1}{b_0},\quad X\equiv 2b_0\ln\!\frac{\mu}{\Lambda}. \] Rearrange: \[ \ln u = \frac{X-u}{a} \quad\Rightarrow\quad u\,e^{u/a} = e^{X/a}. \] Multiply both sides by \(\tfrac{1}{a}\) and set \(W\equiv \tfrac{u}{a}\): \[ W e^{W} = \frac{1}{a} e^{X/a}. \] Thus \[ W = W_k\!\Big(\frac{1}{a}e^{X/a}\Big), \] where \(W_k\) is the Lambert‑W function (multi‑branched). The Lambert‑W is defined by \(W e^{W}=z\) and is the canonical inverse of \(z\mapsto W e^{W}\). [NIST Digital Library of Mathematical Functions](https://dlmf.nist.gov/4.13) [Wikipedia](https://en.wikipedia.org/wiki/Lambert_W_function)


Final explicit expression for the running coupling

Solving back for \(g^2=1/u\) yields one convenient closed form (choose branch \(k\) to get real positive \(g^2\)): \[ \boxed{\; g^2(\mu)=\frac{1}{u(\mu)} = \frac{1}{a\,W_k\!\big(\tfrac{1}{a}e^{X/a}\big)} = -\frac{1}{b_1}\,\frac{1}{1+W_k\!\Big(-\frac{1}{b_1}\Big(\frac{\mu}{\Lambda}\Big)^{-2b_0/b_1}\Big)} \; }. \] For large \(\mu\) the principal branch \(k=0\) reproduces the usual two‑loop asymptotic expansion; near the scale where the logarithm vanishes the other branch behavior encodes the approach to strong coupling. [Wikipedia](https://en.wikipedia.org/wiki/Lambert_W_function) [web2.ph.utexas.edu](https://web2.ph.utexas.edu/~vadim/Classes/2019f/qcd-beta.pdf)


Practical notes and important points

If you want, I can show the explicit algebraic manipulations line‑by‑line from the implicit equation to the boxed Lambert form and then plot \(g(\mu)\) for QCD with physical \(b_0,b_1\).

Patrick:
Okay, let's do it.

Copilot:
Brief answer: Starting from \(\beta(g)=-b_0g^3-b_1g^5\) and setting \(u\!=\!1/g^2\) one obtains \(u+\dfrac{b_1}{b_0}\ln u=2b_0\ln(\mu/\Lambda)\). That transcendental equation is solved exactly by the Lambert‑W function; the algebraic steps below show the change of variables and the explicit inversion, with notes on branch choice and the large‑\(\mu\) expansion.

Derivation: from two‑loop implicit relation to Lambert‑W

Start with the implicit two‑loop relation (derived by integrating the RG after \(u\!=\!1/g^2\)): \[ u + a\ln u = X, \qquad a\equiv\frac{b_1}{b_0},\quad X\equiv 2b_0\ln\!\frac{\mu}{\Lambda}. \]

1. Isolate the logarithm \[ \ln u = \frac{X-u}{a}. \]

2. Exponentiate both sides \[ u = \exp\!\Big(\frac{X-u}{a}\Big) \quad\Rightarrow\quad u\,e^{u/a} = e^{X/a}. \]

3. Introduce the Lambert‑W combination.

Multiply both sides by \(1/a\) and set \[ W\equiv \frac{u}{a}. \] Then \[ W e^{W} = \frac{1}{a}e^{X/a}. \]

4. Invert with Lambert‑W. By definition \(W_k(z)\) solves \(W e^{W}=z\), so \[ W = W_k\!\Big(\frac{1}{a}e^{X/a}\Big). \]

5. Return to \(g^2\). Since \(u=aW\) and \(g^2=1/u\), \[ \boxed{\,g^2(\mu)=\frac{1}{a\,W_k\!\big(\tfrac{1}{a}e^{X/a}\big)}\,} \] or, substituting \(a=b_1/b_0\) and \(X=2b_0\ln(\mu/\Lambda)\), one convenient algebraic rearrangement is \[ \boxed{\,g^2(\mu)= -\frac{1}{b_1}\,\frac{1}{1+W_k\!\Big(-\frac{1}{b_1}\Big(\frac{\mu}{\Lambda}\Big)^{-2b_0/b_1}\Big)}\, }. \]

Branch choice and asymptotic expansion

Practical notes

If you want, I can (a) show the same steps with explicit numeric QCD \(b_0,b_1\) and plot \(g(\mu)\) vs \(\mu\), or (b) derive the implicit relation \(u+\tfrac{b_1}{b_0}\ln u=2b_0\ln(\mu/\Lambda)\) directly from the two‑loop β‑function step‑by‑step.



Afterword: Unfortunately, I have to terminate this chat somewhere.