Geometric Calculus as a foundation to algebraic geometry?

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Geometric Calculus as a foundation to algebraic geometry?

Patrick Reany

28 May 2026

Note: This chat I had with Copilot is likely edited for relevance and brevity. I often do not take the time to highlight all the words that Copilot highlights. Further, in the interest of being didactic, I might arbitrarily highlight an occasional word or phrase that Copilot did not. (Naturally, I get to correct my spelling, grammar, and other minor errors for free.)

I report as faithfully as I can what LLMs tell me, but I can't guarantee that they are correct on every factual matter. If the subject should touch on physical or mental self-care, regard the content merely for information sake, rather than medical advice.




Patrick:
Is anyone trying to construct modern (or classical) algebraic geometry on top of geometric calculus, or are the two subjects just too different to mesh them together?

Copilot:
Short answer: no one has successfully built algebraic geometry “on top of” geometric calculus, and the two frameworks are far enough apart in foundations, aims, and methods that no existing research program has merged them in a systematic way. But the longer answer is more interesting: there are conceptual bridges, and one can see why the merger hasn’t happened yet — and what a plausible path would look like.


1. What geometric calculus is (and why it’s hard to use as a foundation for AG) Geometric Calculus (GC), in the Hestenes–Sobczyk sense, is:

GC is a differential theory. It presupposes:

This is the opposite of the algebraic geometry ethos, which is:

GC is “too rigid” and “too smooth” to serve as a base for AG.


2. What algebraic geometry needs that GC doesn’t provide

Algebraic geometry requires:

Clifford algebras are:

So GC simply does not supply the algebraic primitives AG is built from.


3. Are there partial bridges? Yes — but they stop short of a merger.

(A) Clifford algebra in algebraic geometry

There is a well-developed theory of Clifford algebras of quadratic forms over schemes.
This is classical: Grothendieck, Knus, Lam, and many others.

But this is not geometric calculus.
It is purely algebraic and does not include:

It’s Clifford algebra stripped of all analytic structure.

(B) Derived algebraic geometry and higher categories

One might imagine GC fitting into DAG via:

But GC is too tied to classical smoothness and metric structure to fit naturally into these categorical frameworks.

(C) Noncommutative geometry (Connes)

This is the closest conceptual cousin to GC, because both:

But Connes’ NCG is operator-algebraic and spectral, not multivector-calculus-based. No one has merged GC with NCG in a way that touches AG.

(D) Algebraic integral geometry

There is a field called algebraic integral geometry, but it is unrelated to GC and does not use Clifford calculus. [arXiv.org](https://arxiv.org/pdf/1004.3145)


4. Why no one has built algebraic geometry on GC

Three structural obstacles:

1. Algebraic geometry is fundamentally commutative; GC is not.

AG needs commutative rings.
GC is built on Clifford algebras, which are noncommutative.

2. AG is metric-free; GC is metric-dependent.

AG works over arbitrary fields, even finite fields.
GC requires a metric to define the Clifford product.

3. AG is sheaf-theoretic; GC is differential-operator-theoretic.

GC’s vector derivative is not a sheaf-theoretic object.
AG’s structure sheaf has no natural place for GC’s analytic machinery.


5. Is anyone trying?

Based on available literature:

There is zero evidence of an attempt to build AG on GC.


6. Could it be done in principle?

Only if one radically reinterprets both subjects.

A hypothetical path would require:

At that point, the resulting theory would no longer be GC in the Hestenes sense.


7. The philosophical bottom line

GC is a differential, metric, analytic language.
AG is a commutative, metric-free, algebraic language.

They live in different worlds.

The only place they “touch” is in the classical theory of Clifford algebras of quadratic forms — but that is a tiny overlap, and it does not involve geometric calculus.


Final answer

No, there is no research program constructing algebraic geometry on top of geometric calculus. The two frameworks differ too deeply in foundations — commutativity, smoothness, metric dependence, and sheaf-theoretic structure — for a natural merger. The only overlap is the algebraic theory of Clifford algebras, which does not involve GC’s differential machinery.

If you want, I can sketch what a hypothetical “Clifford-scheme” theory would need to look like, or map out the conceptual obstacles in more detail.

Patrick:
Perhaps there are two possible ways to bring them together (maybe more): Make the geometric structures of algebraic geometry smoother (so this is a restricted form of it), or build your commutative ring out of the bivectors of a geometric algebra (of even order vector space), not out of its vectors.

Copilot:
You’re doing exactly the right kind of move here—don’t ask “is there a literature?”, ask “what could be made to work structurally?” Let’s take your two proposals seriously and push them until they either crack or reveal something interesting.


1. “Smoothifying” algebraic geometry and then layering geometric calculus

This is the “restrict AG to its smooth, real/complex, metric-friendly part” idea.

Natural habitat for this:

So in this sense, GC can sit on top of the analytic avatar of algebraic geometry. But notice what’s happening:

That’s coherent, but it’s not “rebuilding AG on GC”—it’s “using GC as the differential language on the smooth locus of real/complex varieties.”

If you’re okay with that restriction, then a real project could be:

That’s not crazy at all. It’s just not foundational; it’s an overlay.


2. Building commutative rings from bivectors of a geometric algebra

This is the more radical idea: use the bivectors of a geometric algebra as the “ring of functions” (or at least as a commutative algebra) and then try to run scheme-like constructions.

Let’s unpack the algebra first.

2.1. What structure do bivectors have?

Start with a geometric algebra \(Cl(V, Q)\) over a field \(k\) (say \(k = \mathbb{R}\) for now).

So: the bivector space is not naturally a commutative ring under any of the standard products.

2.2. Can we force a commutative product?

You could try:

So \((\Lambda^2 V, \circ)\) is not a commutative associative algebra in any clean way.

The moment you insist on:

you’re basically pushed back toward:

Neither gives you a standard commutative ring on bivectors alone that you could feed into the scheme machine.

2.3. Where bivectors do appear algebraically

There is a beautiful algebraic geometry of bivectors, but it looks different:

So AG already knows a lot about bivectors—but via exterior algebra, not via the full geometric algebra product.

If you say “build your commutative ring out of bivectors,” the closest honest answer is:

That’s standard AG territory, just phrased in GA language.


3. Where your two ideas actually meet

There is a conceptual sweet spot between your two proposals:

Then:

So instead of “build the structure sheaf from bivectors,” a more viable synthesis is:

That’s a genuine interaction, even if it’s not a foundational unification.


If you want to push this further, I’d be curious which direction feels more alive to you right now:

Patrick:
Let's begin with tightening the smooth/metric overlay on real/complex varieties.

Copilot:
Good choice — tightening the smooth/metric overlay is the most promising, concrete route. Below I give a compact roadmap you can follow to turn that idea into a usable research program or a sequence of projects: what to build, how to build it, what algebraic invariants you can recover with geometric calculus, and what is inevitably lost when you pass from algebraic geometry to its smooth/metric avatar.

Overview


Concrete construction steps

1. Choose the algebraic input

2. Pass to the analytic manifold

3. Pick a metric compatible with the algebraic structure

4. Build the Clifford bundle and spinor bundles

5. Install geometric calculus operators

6. Translate classical differential forms into multivectors

7. Integrate and pair with algebraic cycles


How geometric calculus can express algebraic-geometric invariants


Limitations and what you lose


Concrete research projects and milestones

1. Worked example project

2. GC formulation of Chern–Weil

3. Dirac operator and algebraic index

4. Extension across singularities

5. Numerical and computational angle


Suggested references and background to consult


If you want, I can now produce a concrete worked example: pick a smooth projective curve (genus 1 or 2) or a Kähler surface, choose a canonical metric, and write out the Clifford bundle, curvature bivectors, and a GC-style computation of one Chern number step by step. I’ll include explicit formulas and a short computation you can check numerically.

Patrick:
Let's go with your suggestion and you can decide the examples to use.

Copilot:
Plan and chosen examples

Goal: start from smooth projective varieties, equip their analytic manifolds with canonical metrics, build the Clifford bundle and geometric calculus objects, then compute standard algebraic invariants (Chern numbers, Euler characteristic, intersection numbers) in GC language.

Examples I’ll work through

These examples are canonical, simple, and already have well-known algebraic invariants to compare with GC computations.


Step 1 Build the analytic and metric data

From algebraic variety to metric manifold

  1. Start with a smooth projective variety \(X\) over \(\mathbb{C}\). Pass to the complex manifold \(X(\mathbb{C})\).
  2. Choose a canonical metric: 3. From the metric \(g\) form the tangent bundle \(TX\), the cotangent bundle \(T^*X\), and the associated Clifford bundle \(Cl(TX,g)\). If a spin or spin\(^c\) structure exists, form the corresponding spinor bundle.


Step 2 Represent curvature and characteristic forms in geometric calculus

Key identifications

Chern–Weil in GC language


Step 3 Worked Riemann surface computations

Gauss–Bonnet via geometric calculus

Check on examples

These are compact, explicit checks showing how curvature-as-bivector plus GC integration recovers algebraic-topological invariants.


Step 4 Worked surface computation for \(\mathbb{CP}^2\)

Algebraic invariants to recover

GC route

  1. Equip \(\mathbb{CP}^2\) with the Fubini–Study metric. Compute the Chern connection on \(T\mathbb{CP}^2\) and its curvature 2-form \(F\).
  2. Interpret \(F\) pointwise as a bivector-valued endomorphism \(\mathcal{F}\) in the Clifford algebra.
  3. Use Chern–Weil: \[ c_1 = \frac{i}{2\pi}\operatorname{Tr}(F),\qquad c_2 = \frac{1}{8\pi^2}\big(\operatorname{Tr}(F\wedge F) - \operatorname{Tr}(F)\wedge\operatorname{Tr}(F)\big) \] and translate wedge products and traces into GC operations (wedge \(\leftrightarrow\) outer product; traces realized via contraction and scalar part extraction in the Clifford algebra).
  4. Integrate the resulting scalar top forms over \(\mathbb{CP}^2\) using GC directed integrals to obtain the numbers \(9\) and \(3\).

Why this works cleanly here


Step 5 Practical computation and numerics

Symbolic computation

Numerical approach

Checks to run


What you gain and what remains delicate

Gains

Delicate points


Next concrete step I can do now

I can produce a fully worked symbolic computation for one of the examples above. Options (I’ll pick one unless you prefer another):

Tell me which option you want me to carry out now, or I’ll proceed with Option A and give the full step-by-step GC derivation for Gauss–Bonnet on the sphere and torus.

Patrick:
Let's go with Option A.

Copilot:
Short answer: I’ll derive the Gauss–Bonnet theorem in geometric‑calculus language for closed surfaces, then evaluate it on the sphere and the flat torus to recover \(\chi=2\) and \(\chi=0\).

Setup and statement of Gauss–Bonnet

Let \(X\) be a compact oriented 2‑dimensional Riemannian manifold with area form \(dA\) and Gaussian curvature \(K\). The Gauss–Bonnet theorem states \[ \frac{1}{2\pi}\int_X K\,dA=\chi(X), \] where \(\chi(X)\) is the Euler characteristic. [Wikipedia](https://en.wikipedia.org/wiki/Gauss%E2%80%93Bonnet_theorem) [Department of Mathematics | The University of Chicago](https://www.math.uchicago.edu/~may/VIGRE/VIGRE2010/REUPapers/Rotskoff.pdf)


Geometric calculus translation


GC derivation of Gauss–Bonnet

    1. Local reduction. In two dimensions the full curvature tensor has only one degree of freedom; GC packages it as \(\mathcal{R}=K I\). 2. Global integral. Use the directed integral of the curvature bivector and extract the scalar part: \[ \int_X \langle \mathcal{R} I^{-1}\rangle_0\,dV = \int_X K\,dA. \] 3. Topological identification. By the classical Gauss–Bonnet theorem the left side divided by \(2\pi\) equals \(\chi(X)\). Thus in GC language \[ \boxed{\;\chi(X)=\frac{1}{2\pi}\int_X \langle \mathcal{R} I^{-1}\rangle_0\,dV\; }. \] This is the same content as standard proofs but expressed entirely with multivectors, contractions, and directed integrals. [Wikipedia](https://en.wikipedia.org/wiki/Gauss%E2%80%93Bonnet_theorem)


Examples computed in GC language

Both checks match the algebraic/topological values and show how GC packages curvature and integration compactly. [UCB Mathematics](https://math.berkeley.edu/~alanw/240papers00/zhu.pdf)


Key takeaways

Patrick:
Let's proceed with your suggestion.

Copilot:
Short answer: Below is a full, explicit coordinate‑level derivation of Gauss–Bonnet for the round sphere in geometric‑calculus language (curvature as a bivector \(\mathcal{R}=K I\), contraction with the unit pseudoscalar, and the directed integral), followed by the numerical evaluation giving \(\chi(S^2)=2\).


1. Metric, orthonormal coframe, and area pseudoscalar

Use spherical coordinates \((\theta,\varphi)\) on the sphere of radius \(R\) with the standard metric \[ ds^2 = R^2(d\theta^2+\sin^2\theta\,d\varphi^2). \] Choose the orthonormal coframe \[ \boldsymbol{\theta}^1 = R\,d\theta,\qquad \boldsymbol{\theta}^2 = R\sin\theta\,d\varphi. \] The local pseudoscalar (unit area bivector) is \[ I=\boldsymbol{\theta}^1\wedge\boldsymbol{\theta}^2, \] and the Riemannian area form is \(dA = \boldsymbol{\theta}^1\wedge\boldsymbol{\theta}^2 = R^2\sin\theta\,d\theta\wedge d\varphi\).

*(Background on local Gauss–Bonnet and area forms.) [Harvard Mathematics Department](https://people.math.harvard.edu/~knill/teaching/math136/handouts/lecture15.pdf) [Wikipedia](https://en.wikipedia.org/wiki/Gauss%E2%80%93Bonnet_theorem)


2. Levi‑Civita connection 1‑form (frame method)

For a 2‑manifold with orthonormal coframe \(\{\boldsymbol{\theta}^i\}\) the connection 1‑form \(\omega\) satisfies Cartan’s first structure equation \(d\boldsymbol{\theta}^i+\omega^i{}_j\wedge\boldsymbol{\theta}^j=0\). In two dimensions there is a single independent connection 1‑form \(\omega=\omega^1{}_2\). A direct computation gives \[ \omega = -\cos\theta\,d\varphi. \] (One checks \(d\boldsymbol{\theta}^1+\omega\wedge\boldsymbol{\theta}^2=0\) and the analogous equation for \(\boldsymbol{\theta}^2\).) [Harvard Mathematics Department](https://people.math.harvard.edu/~knill/teaching/math136/handouts/lecture15.pdf)


3. Curvature 2‑form and Gaussian curvature

The curvature 2‑form is \(\Omega=d\omega\). Compute \[ \Omega = d(-\cos\theta\,d\varphi)=\sin\theta\,d\theta\wedge d\varphi. \] Relate \(\Omega\) to the area form: \[ \Omega = \frac{1}{R^2}\,dA. \] Thus the Gaussian curvature is \[ K=\frac{1}{R^2}. \] (Equivalently \(\Omega=K\,I\) when \(I\) is identified with the area form.) [Wikipedia](https://en.wikipedia.org/wiki/Gauss%E2%80%93Bonnet_theorem) [Harvard Mathematics Department](https://people.math.harvard.edu/~knill/teaching/math136/handouts/lecture15.pdf)


4. Geometric‑calculus packaging and integral

In geometric calculus represent the curvature as the bivector field \[ \mathcal{R}=K\,I. \] Extract the scalar curvature density by contracting with \(I^{-1}\) and taking the scalar part: \[ \langle \mathcal{R} I^{-1}\rangle_0 = K. \] The directed integral of this scalar density over the surface reproduces the usual curvature integral: \[ \int_{S^2}\langle \mathcal{R} I^{-1}\rangle_0\,dV=\int_{S^2}K\,dA. \]


5. Evaluate and conclude

For the sphere, \[ \int_{S^2}K\,dA = \frac{1}{R^2}\int_{S^2}dA=\frac{1}{R^2}\cdot 4\pi R^2=4\pi. \] Dividing by \(2\pi\) yields the Euler characteristic \[ \chi(S^2)=\frac{1}{2\pi}\int_{S^2}K\,dA=2, \] as required by Gauss–Bonnet. [Wikipedia](https://en.wikipedia.org/wiki/Gauss%E2%80%93Bonnet_theorem) [Harvard Mathematics Department](https://people.math.harvard.edu/~knill/teaching/math136/handouts/lecture15.pdf)


If you’d like, I can now (a) write the same computation fully in index/frame algebra showing each Cartan equation step-by-step, or (b) perform the analogous GC computation for a flat torus (explicitly showing \(\mathcal{R}=0\) and \(\chi=0\)). Which would you prefer?

Patrick:
Earlier you suggested that we could rephrase Grassmannian/Plücker geometry and curvature in a bivector–GC language. Can we pursue that now?

Copilot:
I'll pull together a focused, usable bridge between Grassmannian / Plücker geometry and a bivector–geometric‑calculus (GC) viewpoint: what is already algebraically true about bivectors, where Clifford/Ga geometric algebra can add structure (metric, contractions, Dirac/Clifford traces), and concrete projects you can try that genuinely mix AG and GC. First I’ll run a quick web grounding search for the core algebraic facts (Plücker embedding, decomposable bivectors, coordinate rings) and then give the plan and worked ideas.

Searching for core references now.

Patrick:
Excellent. Ready?

Copilot:
Grassmannian and Plücker geometry — core algebraic facts

These are the algebraic footholds you can build on; they treat bivectors as coordinates or points, not as a ring.


How a metric and Clifford algebra enrich bivector geometry


Recasting curvature and classical invariants in bivector–GC language


Concrete projects that genuinely mix Plücker geometry and GC

1. Metric Plücker geometry

2. Clifford‑sheaf on Grassmannian 3. Plücker relations via GC identities 4. Klein quadric and line geometry in GC 5. Curvature and Plücker coordinates of tangent 2‑planes


Low‑dimensional worked examples to try first


Practical next steps and computational tools


If you want, I’ll now produce one concrete worked computation: either (A) the Plücker embedding and quadratic relation for \(Gr(2,4)\) written in Clifford language and shown to detect intersecting lines, or (B) the selfdual/anti‑selfdual decomposition of a 4D curvature bivector and its expression of the Pfaffian via Clifford traces. Which should I do next?

Patrick:
Let's go with Option A.

Copilot:
Short answer: Yes — for \( \mathrm{Gr}(2,4) \) the Plücker quadric and incidence relations admit a clean bivector/Clifford‑algebra reformulation: decomposable bivectors are exactly those whose wedge square vanishes, and the Klein quadric equation is the single quadratic Plücker relation in coordinates. [Wikipedia](https://en.wikipedia.org/wiki/Pl%C3%BCcker_coordinates) [grokipedia.com](https://grokipedia.com/page/Pl%C3%BCcker_coordinates)

1. Algebraic setup (Plücker coordinates for \(Gr(2,4)\))

Let \(V\cong k^4\) with basis \(e_1,\dots,e_4\). A 2‑plane spanned by vectors \(u,v\in V\) is represented by the decomposable bivector \[ B=u\wedge v=\sum_{1\le i\lt j\le4} p_{ij}\,e_i\wedge e_j, \] where the Plücker coordinates \(p_{ij}=u_i v_j-u_j v_i\) are homogeneous coordinates on \(\mathbb{P}(\Lambda^2 V)\). The image of \(Gr(2,4)\) is the Klein quadric cut out by the single quadratic Plücker relation \[ p_{12}p_{34}-p_{13}p_{24}+p_{14}p_{23}=0. \] This is the classical Plücker description of lines in \(\mathbb{P}^3\). [Wikipedia](https://en.wikipedia.org/wiki/Pl%C3%BCcker_coordinates)

2. Exterior algebra criterion (decomposability)

A bivector \(B\in\Lambda^2 V\) is decomposable (i.e., \(B=u\wedge v\)) iff its wedge square vanishes: \[ B\wedge B=0\in\Lambda^4 V. \] In coordinates this vanishing is exactly the quadratic Plücker relation above; algebraically the Plücker ideal encodes the condition \(B\wedge B=0\). [Wikipedia](https://en.wikipedia.org/wiki/Pl%C3%BCcker_coordinates)

3. Clifford algebra packaging and the grade‑4 test

Equip \(V\) with a nondegenerate metric and form the Clifford algebra \(Cl(V)\). The geometric product of a bivector with itself decomposes into homogeneous parts; the grade‑4 part of \(B^2\) is (up to a nonzero scalar depending on conventions) the exterior square \(B\wedge B\). Thus in the Clifford algebra language the decomposability test becomes the single algebraic condition \[ \langle B^2\rangle_4 = 0, \] which is equivalent to the Plücker quadric. (This is a natural inference from the identification of wedge powers with grade projections in geometric algebra; see also work using Clifford methods to solve Plücker relations.) [Uppsala University](https://uu.diva-portal.org/smash/get/diva2:1909663/FULLTEXT01.pdf) [grokipedia.com](https://grokipedia.com/page/Pl%C3%BCcker_coordinates)

4. Incidence and intersection via Clifford inner products

With a metric, \(\Lambda^2 V\) carries an inner product. For two Plücker bivectors \(B_1,B_2\) representing lines in \(\mathbb{P}^3\), incidence/intersection conditions can be expressed by bilinear forms in Plücker coordinates: a standard bilinear contraction vanishes exactly when the corresponding lines meet (this is the classical incidence test in Plücker language). In Clifford terms the scalar part \(\langle B_1 B_2\rangle_0\) (or an equivalent bilinear pairing) encodes that same incidence relation, so GC provides a metric‑aware, computationally convenient test for intersection. [Wikipedia](https://en.wikipedia.org/wiki/Pl%C3%BCcker_coordinates) [grokipedia.com](https://grokipedia.com/page/Pl%C3%BCcker_coordinates)

5. Concrete next steps you can run

If you want, I’ll now produce the explicit symbolic expansion for \(B\wedge B\) in basis coordinates (showing the Klein quadric term-by-term) and then translate that same computation into Clifford grade projections so you can run it directly in a CAS. Which would you prefer?

Patrick:
Yes, let's proceed as you suggest.

Copilot:
Short answer: Decomposability of a bivector in \(\Lambda^2 V\) is equivalent to the vanishing of its wedge square; for \(V\cong k^4\) this single quadratic condition is the Klein quadric (the Plücker relation). In geometric algebra the same test is the vanishing of the grade‑4 part of \(B^2\). [Mathematics Stack Exchange](https://math.stackexchange.com/questions/5021385/basis-free-and-geometric-proof-of-pl%c3%bccker-relations) [Wikipedia](https://en.wikipedia.org/wiki/Pl%C3%BCcker_embedding)

Algebraic statement in coordinates

Let \(V\) have basis \(e_1,\dots,e_4\). Write a general bivector \[ B=\sum_{1\le i\lt j\le4} p_{ij}\,e_i\wedge e_j. \] The decomposability criterion is \[ B\ \text{is decomposable}\quad\Longleftrightarrow\quad B\wedge B=0, \] and for \(4\)-dimensional \(V\) this single scalar equation expands to the classical Plücker quadratic \[ p_{12}p_{34}-p_{13}p_{24}+p_{14}p_{23}=0. \] This is exactly the equation of the Klein quadric in \(\mathbb{P}(\Lambda^2 V)\). [Wikipedia](https://en.wikipedia.org/wiki/Pl%C3%BCcker_embedding)

Explicit expansion (symbolic)

Compute \(B\wedge B\) in the ordered basis \(e_1\wedge e_2\wedge e_3\wedge e_4\). Only complementary index pairs contribute, and one finds \[ B\wedge B =2\big(p_{12}p_{34}-p_{13}p_{24}+p_{14}p_{23}\big)\; e_1\wedge e_2\wedge e_3\wedge e_4. \] Thus the scalar coefficient multiplying the volume form is the Plücker quadratic; setting it to zero is equivalent to \(B\wedge B=0\). Important point: the factor \(2\) depends on the wedge normalization; the vanishing condition is independent of that scalar. [Mathematics Stack Exchange](https://math.stackexchange.com/questions/5021385/basis-free-and-geometric-proof-of-pl%c3%bccker-relations)

Clifford algebra reformulation

Equip \(V\) with a nondegenerate metric and form the Clifford algebra \(Cl(V)\). The geometric product of a bivector with itself decomposes by grade: \[ B^2=\langle B^2\rangle_0+\langle B^2\rangle_2+\langle B^2\rangle_4. \] The grade‑4 part \(\langle B^2\rangle_4\) is proportional to the exterior square \(B\wedge B\). Hence the decomposability test becomes the single Clifford condition \[ \boxed{\;\langle B^2\rangle_4=0\;}, \] which is computationally convenient in GC because grade projections are native operations. This recasts the Plücker quadric as a Clifford‑grade vanishing. [Mathematics Stack Exchange](https://math.stackexchange.com/questions/5021385/basis-free-and-geometric-proof-of-pl%c3%bccker-relations)

Incidence and metric tests

With a metric the natural inner product on \(\Lambda^2 V\) gives a bilinear pairing on Plücker coordinates; classical incidence (two lines meet) is detected by a bilinear contraction of their Plücker bivectors. In Clifford language the scalar part \(\langle B_1 B_2\rangle_0\) (or an equivalent contraction) encodes the same incidence condition, making intersection tests algebraically simple and numerically stable in GC. [Wikipedia](https://en.wikipedia.org/wiki/Pl%C3%BCcker_embedding)

How you can run this in a CAS


Afterword: